00:00 - 00:04
the following content is provided under
00:01 - 00:06
a Creative Commons license your support
00:04 - 00:08
will help MIT open courseware continue
00:06 - 00:11
to offer highquality educational
00:08 - 00:12
resources for free to make a donation or
00:11 - 00:15
to view additional materials from
00:12 - 00:18
hundreds of MIT courses visit MIT open
00:15 - 00:18
courseware at
00:20 - 00:28
ocw.mit.edu so again welcome to
00:24 - 00:32
1801 we're getting started today with
00:28 - 00:35
what we're calling unit one highly
00:32 - 00:38
imaginative topic uh highly imaginative
00:35 - 00:38
title and it's
00:42 - 00:47
differentiation so let me first tell you
00:45 - 00:48
briefly what's in store in the next
00:48 - 00:56
weeks the main topic today is what is a
01:03 - 01:06
and we're going
01:07 - 01:13
to look at this from several different
01:10 - 01:16
points of view and the first one is a
01:13 - 01:16
the geometric
01:18 - 01:23
interpretation and that's what we'll
01:19 - 01:26
spend most of today on
01:23 - 01:28
and then we'll also talk about a
01:28 - 01:31
interpretation
01:32 - 01:35
of what a derivative
01:41 - 01:47
then there's going to be something else
01:44 - 01:49
which I guess is maybe the reason why
01:47 - 01:52
calculus is so fundamental and why we
01:49 - 01:55
always start with it uh at in most
01:52 - 01:58
science and engineering schools which is
01:58 - 02:03
importance of derivatives
02:00 - 02:06
of of this to
02:08 - 02:14
measurements so that means pretty much
02:11 - 02:17
every place that means in science and
02:14 - 02:21
engineering in
02:17 - 02:21
economics in uh political
02:22 - 02:29
science Etc uh polling uh lots of
02:26 - 02:32
commercial applications just just about
02:29 - 02:34
everything now so that's what we'll be
02:32 - 02:37
getting started with and then there's
02:34 - 02:38
another thing that we're going to do in
02:38 - 02:46
unit which is we're going to explain how
02:43 - 02:46
to differentiate
02:49 - 02:54
anything so how to differentiate any
02:52 - 02:54
function you
03:02 - 03:06
and that's kind of a tall order but let
03:04 - 03:09
me just give you an example if you want
03:06 - 03:10
to take the derivative this we'll see
03:09 - 03:13
today as the notation for the derivative
03:10 - 03:16
of something of some messy function like
03:13 - 03:19
e to the X AR
03:19 - 03:27
X we'll work this out by the end of this
03:25 - 03:31
unit all right so anything you can think
03:27 - 03:33
of anything you can write down we can
03:31 - 03:38
differentiated all right so that's what
03:33 - 03:40
we're going to do and today as I said
03:38 - 03:43
we're going to spend most of our time on
03:40 - 03:43
this geometric
03:44 - 03:48
interpretation so let's let's begin with
03:49 - 03:55
that so here we go with the
03:57 - 04:04
interpretation of uh
04:05 - 04:12
and what we're going to
04:08 - 04:16
do is just ask the geometric problem of
04:12 - 04:16
finding the tangent
04:24 - 04:31
some graph of some function at some
04:31 - 04:39
which is say x0 y0 so that's the problem
04:35 - 04:41
that we're addressing here um guess I
04:39 - 04:46
should probably turn this
04:41 - 04:48
off all right so here's our problem and
04:46 - 04:51
now let me show you the
04:51 - 04:55
so well let's graph the
04:57 - 05:04
function so let's say here's its graph
05:00 - 05:06
and here's some point all right maybe I
05:04 - 05:08
should draw it just a bit lower so that
05:08 - 05:12
don't all right so here's a point P
05:12 - 05:18
it's above the point
05:15 - 05:22
x0 x0 by the way this was supposed to be
05:18 - 05:24
an x0 that was the some fixed place on
05:26 - 05:34
axis and now in order to perform this
05:30 - 05:37
this Mighty feat I will
05:34 - 05:42
um use another color of chalk how about
05:37 - 05:45
red okay so so here it is there's the
05:42 - 05:49
tangent line well not quite straight
05:45 - 05:50
close enough right I did it all right
05:49 - 05:54
that's the end that's the geometric
05:50 - 05:57
problem I achieved what I wanted to do
05:54 - 06:00
and uh it's kind of an interesting
05:57 - 06:02
question which unfortunately I can't
06:00 - 06:04
solve for you in this class which is how
06:02 - 06:07
did I do that that is how physically did
06:04 - 06:09
I manage to know what to do to draw this
06:07 - 06:12
tangent line but that's what geometric
06:09 - 06:14
problems are like um we visualize it we
06:12 - 06:17
can figure it out somewhere in our
06:14 - 06:20
brains it happens and the task that we
06:17 - 06:26
have now is to figure out how to do it
06:20 - 06:29
analytically to do it in a way that uh a
06:26 - 06:31
machine could do just as well as I did
06:29 - 06:34
in drawing this tangent
06:34 - 06:41
so so what do we learn in high school
06:38 - 06:44
about what a tangent line is well a
06:41 - 06:46
tangent line has an equation and any
06:44 - 06:51
line through Point has the equation y -
06:46 - 06:55
y0 is equal to M the slope time x - x0
06:51 - 06:58
so so here's the
06:55 - 07:01
the equation for that
06:58 - 07:04
line and now there are two pieces of
07:01 - 07:05
information that we're going to need to
07:05 - 07:10
out uh what the line is the first one is
07:10 - 07:18
point that's that point P there and to
07:13 - 07:20
specify P given given X we need to know
07:18 - 07:23
the uh the the level of Y which is of
07:20 - 07:25
course just f ofx z now that's that's
07:23 - 07:28
not a calculus problem but anyway that's
07:25 - 07:31
a very important part of the process so
07:28 - 07:34
that's the first thing we need to
07:31 - 07:38
know and the second thing we need to
07:38 - 07:45
slope and that's this number
07:41 - 07:50
M and in calculus we have another name
07:45 - 07:53
for it we call it frime of x0 namely the
07:50 - 07:54
derivative of f so that's the calculus
07:53 - 07:57
part that's the tricky part and that's
07:54 - 08:00
the part that we have to discuss
07:57 - 08:02
now so just to make that
08:00 - 08:06
uh explicit here I'm going to make a
08:02 - 08:10
definition which is that frime of
08:06 - 08:10
x0 which is known as the
08:12 - 08:17
derivative of
08:17 - 08:25
x0 all right is the
08:25 - 08:31
of the tangent
08:35 - 08:44
FX at the point
08:40 - 08:44
uh uh let's just call it
08:52 - 08:58
so so that's what it is but still I
08:55 - 09:01
haven't made any progress in figuring
08:58 - 09:04
out any better how I drew that line so I
09:01 - 09:06
have to say something that's more
09:04 - 09:08
concrete because I want to be able to
09:06 - 09:12
cook up what these numbers are I have to
09:08 - 09:14
figure out what this number m is uh and
09:12 - 09:18
one way of thinking about that let me
09:14 - 09:19
just uh try it is so I certainly am
09:18 - 09:21
taking for granted the sort of
09:19 - 09:23
non-calculus part that I know what a
09:21 - 09:26
line through a point is so I know this
09:23 - 09:28
equation but another possibility might
09:26 - 09:30
be you know this line here how do I know
09:28 - 09:33
well fortunately I didn't draw it quite
09:30 - 09:37
straight but there it is how do I know
09:33 - 09:43
that this orange line is not a tangent
09:37 - 09:43
line but this other line is a tangent
09:48 - 09:54
well it's it's actually not so obvious
09:52 - 09:57
and but I'm going
09:54 - 09:59
to describe it a little bit it's it's
09:57 - 10:02
not really the fact this thing crosses
09:59 - 10:05
at some other place which is this point
10:02 - 10:07
q but it's not really the fact that the
10:05 - 10:09
thing crosses at two place because the
10:07 - 10:11
line could be Wiggly the curve could be
10:09 - 10:13
Wiggly and it could cross back and forth
10:11 - 10:16
a number of times that's not what
10:13 - 10:19
distinguishes the tangent
10:16 - 10:22
line so I'm going to have to somehow
10:19 - 10:26
grasp this and I first do it in
10:22 - 10:31
language and it it's the following idea
10:26 - 10:35
it's that if you take this orange line
10:31 - 10:38
which is uh called a secant line and you
10:35 - 10:42
think of the Q the point Q is getting
10:38 - 10:44
closer and closer to P then the slope of
10:42 - 10:47
that line will get closer and closer to
10:44 - 10:53
the slope of the red
10:47 - 10:54
line and if we draw it close enough then
10:53 - 10:56
that's going to be the correct line so
10:54 - 10:59
that's really what I did sort of in my
10:56 - 11:00
brain when I drew that first line and so
10:59 - 11:04
that's the way I'm going to articulate
11:00 - 11:04
it first now so the tangent
11:07 - 11:16
line is equal to the
11:11 - 11:16
limit of what so-called secant
11:20 - 11:27
PQ as Q TS to p and here we're thinking
11:25 - 11:30
of p is being
11:27 - 11:34
fixed and Q is
11:30 - 11:36
varying all right so so that's
11:34 - 11:40
the the G again this is still a
11:36 - 11:41
geometric discussion but now uh we're
11:40 - 11:44
going to be able to put symbols and
11:41 - 11:48
formulas to this computation and we'll
11:44 - 11:50
be able to um to work out uh formulas in
11:55 - 12:00
so so let's do
11:57 - 12:04
that so so first of
12:00 - 12:07
all I'm going to write out these points
12:04 - 12:10
p and Q again so maybe we'll put P
12:10 - 12:14
here and I'm thinking of this line
12:12 - 12:17
through them I guess it was orange so
12:14 - 12:19
we'll leave it as
12:19 - 12:26
right and now I want to compute its
12:23 - 12:28
slope and so this is gradually we'll do
12:26 - 12:30
this in two steps and these steps will
12:28 - 12:32
introduce to the basic notations which
12:30 - 12:35
are used throughout calculus including
12:32 - 12:39
multivariable calculus across the board
12:35 - 12:42
so the first notation that's used is you
12:39 - 12:45
imagine here's the x-axis underneath and
12:42 - 12:49
here's the x0 the location directly
12:45 - 12:52
below the point p and we're traveling
12:49 - 12:55
here a horizontal distance which is
12:52 - 12:58
denoted by Delta X so
12:55 - 13:01
that's Delta X
12:58 - 13:04
socaled and we could also call it the
13:06 - 13:11
X all right so that's one thing we want
13:09 - 13:13
to measure in order to get the slope of
13:11 - 13:16
this line PQ and the other thing is this
13:13 - 13:18
height so that's this distance here
13:16 - 13:21
which we denote Delta F which is the
13:21 - 13:28
F and then the
13:24 - 13:29
slope is just the ratio Delta F over
13:29 - 13:36
so this is the slope of
13:39 - 13:43
secant and the process I just described
13:41 - 13:46
over here with this
13:43 - 13:48
limit applies not just to the whole line
13:46 - 13:50
itself but also in particular to its
13:48 - 13:54
slope and the way we write that is the
13:50 - 13:57
limit as Delta X goes to zero and that's
13:54 - 14:01
going to be our slope so this is the
13:57 - 14:01
slope of the tangent line
14:15 - 14:22
now this is still a little a little
14:19 - 14:26
general and I'm going to I want to work
14:22 - 14:29
out a more usable form here I want to
14:26 - 14:32
work out a better formula for this and
14:29 - 14:36
in order to do that I'm going to write
14:32 - 14:40
Delta F the numerator more explicitly
14:36 - 14:45
here the change in F so remember that
14:40 - 14:45
the point p is the point x0 F of
14:46 - 14:50
x0 all right that's what we got from our
14:48 - 14:55
formula for the
14:50 - 14:56
point and in order to compute these
14:55 - 14:58
distances and in particular the vertical
14:56 - 15:02
distance here I'm going to have to get a
14:58 - 15:06
formula for Q as well so if this
15:02 - 15:10
horizontal distance is Delta X then this
15:06 - 15:14
location is x0 plus Delta
15:10 - 15:15
X and so the point above that point has
15:15 - 15:20
formula which
15:17 - 15:27
is x0 plus uh sorry plus Delta
15:20 - 15:30
x f of and this is a mouthful x0 + Delta
15:32 - 15:35
all right so there's the formula for the
15:33 - 15:38
point Q here's the formula for the point
15:35 - 15:41
p and now I can write a
15:43 - 15:46
formula for the
15:46 - 15:55
derivative which is the following so
15:49 - 15:59
this frime of x0 which is the same as
15:55 - 16:03
m is going to be the limit as Delta X
15:59 - 16:07
goes to zero of the change in F Well the
16:03 - 16:12
change in F is the value of F at the
16:07 - 16:15
upper Point here which is x0 + Delta
16:12 - 16:18
X and minus its value at the lower Point
16:15 - 16:18
P which is f of
16:19 - 16:25
x0 divided by Delta
16:22 - 16:27
X all right so this is the formula I'm
16:25 - 16:30
going to put this in a little box
16:27 - 16:32
because this is by far
16:30 - 16:34
the most important formula today which
16:32 - 16:37
we use to derive pretty much everything
16:34 - 16:41
else and this is the way that we're
16:37 - 16:41
going to be able to compute these
16:45 - 16:50
numbers so let's let's do an
17:06 - 17:11
this example so we'll call this example
17:12 - 17:19
one uh we'll take the function f ofx
17:19 - 17:25
1/x that's sufficiently complicated to
17:22 - 17:27
have an interesting answer and uh
17:25 - 17:30
sufficiently straightforward that we can
17:27 - 17:33
compute the derivative fairly
17:30 - 17:35
quickly so so what is it that we're
17:35 - 17:40
here all we're going to do is we're
17:40 - 17:45
to plug in this this formula here for
17:44 - 17:48
for that function that's that's all
17:45 - 17:51
we're going to do and Visually what
17:48 - 17:54
we're accomplishing is somehow to take
17:51 - 17:57
the hyperbola and take a point on the
17:54 - 18:00
hyperbola and figure
18:00 - 18:03
tangent line all right that's what we're
18:01 - 18:05
accomplishing when we do that so we're
18:03 - 18:09
accomplishing this geometrically but
18:05 - 18:13
we'll be doing it algebraically so first
18:09 - 18:17
we consider this difference Delta F over
18:13 - 18:19
Delta X and write out its formula so I
18:17 - 18:22
have to have a place so I'm going to
18:19 - 18:23
make it again above this point x0 which
18:22 - 18:25
is a general point we'll make the
18:25 - 18:31
calculation so the value of F at the top
18:29 - 18:35
when we move to the right by F ofx so I
18:31 - 18:39
just read off from this read off from
18:35 - 18:45
here the uh the formula the first thing
18:39 - 18:48
I get here is 1 over x0 + Delta X that's
18:45 - 18:50
the leftand term minus
18:48 - 18:53
1x0 that's the right hand term and then
18:50 - 18:56
I have to divide that by Delta
18:53 - 18:59
X okay so here's
18:56 - 19:03
our expression and by by the way this
18:59 - 19:06
has a name this thing is called a
19:09 - 19:13
quotient it's pretty complicated because
19:12 - 19:15
there's always a difference in the
19:13 - 19:16
numerator and in Disguise the
19:15 - 19:19
denominator is a difference because it's
19:16 - 19:21
the difference between the value on the
19:19 - 19:24
right side and the value on the left
19:25 - 19:34
here okay so now
19:30 - 19:36
we're going to simplify it by some
19:34 - 19:39
algebra so let's just take a look so
19:36 - 19:43
this is equal to let's continue on the
19:39 - 19:47
next level here this is equal to 1 /
19:43 - 19:48
Delta x * now all I'm going to do is put
19:47 - 19:52
it over a common
19:48 - 19:57
denominator so the common denominator is
19:52 - 19:59
x0 + Delta x * x0 and so in the
19:57 - 20:02
numerator for the first expression I
19:59 - 20:04
have x0 and for the second expression I
20:02 - 20:07
have x0 + Delta
20:04 - 20:09
X so this is a the same thing as I had
20:07 - 20:12
in the numerator before factoring out
20:09 - 20:17
this denominator and here I put that
20:12 - 20:20
numerator into this more amable form and
20:17 - 20:23
now there are two basic cancellations
20:20 - 20:27
the first one is that x0 and x0
20:23 - 20:27
cancel so we have
20:33 - 20:39
and then the second step is that these
20:37 - 20:42
two expressions cancel right the
20:39 - 20:44
numerator and denominator now we have um
20:42 - 20:48
a cancellation that we can make use of
20:44 - 20:53
so we'll write that under
20:48 - 20:55
here and this is uh equals Min -1 over
20:55 - 21:02
x * x0 and then the very last step is to
21:02 - 21:10
limit as Delta X tends to zero
21:07 - 21:13
and now we can do it before we couldn't
21:10 - 21:16
do it why because the numerator and the
21:13 - 21:18
denominator gave us 0 over Z but now
21:16 - 21:20
that I've made this cancellation I can
21:18 - 21:22
pass to the Limit and all that happens
21:20 - 21:26
is I set this Delta x equal to Z and I
21:22 - 21:27
get minus1 /x 0^ 2ar all right so that's
21:32 - 21:38
right so in other words what I've shown
21:34 - 21:42
let me put it up here is that fime of x0
21:52 - 21:57
2 now uh let's let's look at the graph
21:55 - 22:00
just a little bit to check this for
21:57 - 22:03
plausibility all
22:00 - 22:06
right uh what's Happening Here is first
22:03 - 22:09
of all it's negative right it's less
22:06 - 22:12
than zero which is a good thing you see
22:09 - 22:12
that slope there is
22:16 - 22:23
negative that's the simplest check that
22:19 - 22:26
you could make and the second thing that
22:23 - 22:29
I would just like to point out is that
22:26 - 22:31
as X goes to Infinity that that is if as
22:29 - 22:35
we go farther to the right it gets less
22:31 - 22:38
and less steep so uh
22:35 - 22:41
less and whoops as X go x0 goes to
22:38 - 22:45
Infinity not not zero as x0 goes to
22:41 - 22:48
Infinity less and less
22:45 - 22:50
steep so that's also consistent here is
22:48 - 22:53
when x0 is very large this is a smaller
22:50 - 22:54
and smaller number in in magnitude
22:53 - 22:57
although it's always negative it's
22:54 - 22:57
always sloping
23:01 - 23:05
all right uh so I've managed to fill the
23:03 - 23:08
boards so maybe I should stop for a
23:05 - 23:08
question or two
23:14 - 23:23
yes so the question is to explain again
23:19 - 23:27
this uh limiting process so the formula
23:23 - 23:28
here is We have basically two numbers so
23:27 - 23:32
in other words why is it that this
23:28 - 23:36
expression when Delta x ts to 0 is equal
23:32 - 23:38
to - 1x0 2 let me let me illustrate it
23:36 - 23:41
by sticking in a number for x0 to make
23:38 - 23:45
it more explicit all right so for
23:41 - 23:51
instance let me stick in here for x0 the
23:45 - 23:54
number 3 then it's -1 over 3 + Delta x *
23:51 - 23:56
3 that's the situation that we've got
23:54 - 23:58
and now the question is what happens as
23:56 - 23:59
this number gets smaller and smaller and
23:59 - 24:04
and gets to be practically zero well
24:02 - 24:06
literally what we can do is just plug in
24:04 - 24:09
zero there then you get 3 + 0 * 3 in the
24:06 - 24:11
denominator minus one in the numerator
24:09 - 24:15
so this tends
24:11 - 24:17
to tends to -1 over 9 over 3^
24:15 - 24:20
SAR and that's what I'm saying in
24:17 - 24:24
general with this with this
24:20 - 24:24
extra number here other other
24:25 - 24:32
questions yes how did you simplify
24:29 - 24:35
Del Delta X how you simplify from the
24:32 - 24:35
origal equation
24:36 - 24:44
to so the question is how what happened
24:40 - 24:46
between this step and this step right
24:44 - 24:49
explain this this step here all right so
24:46 - 24:52
there were two parts to that the first
24:49 - 24:55
is this Delta X which was sitting in the
24:52 - 24:58
denominator I factored all the way out
24:55 - 25:00
front and so what's in the parentheses
24:58 - 25:03
is supposed to be the same as what's in
25:00 - 25:06
the numerator of this other expression
25:03 - 25:08
and then at the same time as doing that
25:06 - 25:10
I put that expression which is a
25:08 - 25:12
difference of two fractions I expressed
25:10 - 25:14
it with a common denominator so in the
25:12 - 25:17
denominator here you see the product of
25:14 - 25:18
the denominators of the two fractions
25:17 - 25:21
and then I just figured out what the
25:18 - 25:25
numerator had to be without
25:21 - 25:25
really yeah other
25:27 - 25:37
questions okay okay so
25:31 - 25:41
now uh so I I claim that on the
25:37 - 25:45
whole calculus is uh gets a bad wrap
25:41 - 25:48
that it's um actually easier than than
25:45 - 25:51
most things um but it has there's a
25:48 - 25:55
perception that it's that it's that it's
25:51 - 25:58
harder and so I really have a duty to to
25:55 - 26:01
give you the calculus made harder a
25:58 - 26:03
story here so we we we we have to make
26:01 - 26:05
things harder because that's that's our
26:03 - 26:07
job and this is actually what most
26:05 - 26:09
people do in calculus and it's the
26:07 - 26:14
reason why calculus has a bad reputation
26:09 - 26:17
so the the the secret is that when
26:14 - 26:20
people ask problems in calculus they
26:17 - 26:23
generally ask them in context and there
26:20 - 26:25
are many many other things going on and
26:23 - 26:27
so the little piece of the problem which
26:25 - 26:29
is calculus is actually fairly routine
26:27 - 26:31
and has to be isolated and gotten
26:29 - 26:32
through but all the rest of it relies on
26:31 - 26:35
everything else you learned in
26:32 - 26:38
mathematics up to this stage from grade
26:35 - 26:40
school to through high school so so
26:38 - 26:42
that's the complication so now we're
26:40 - 26:44
going to do a little bit of calculus
26:48 - 26:55
hard by uh uh talking about a word
26:52 - 26:59
problem now we we only have one sort of
26:55 - 27:02
word problem that we can pose because
26:59 - 27:04
all we've talked about is this geometry
27:02 - 27:05
uh uh point of view so so far those are
27:04 - 27:07
the only kinds of word problems we can
27:05 - 27:12
pose so what we're going to do is just
27:07 - 27:16
pose such a problem so find the
27:23 - 27:30
enclosed by the
27:34 - 27:43
tangent to um y =
27:39 - 27:47
1X okay so that's a geometry
27:43 - 27:49
problem and let me draw a picture of it
27:47 - 27:52
it's practically the the same as the
27:49 - 27:54
picture for example one of course so
27:52 - 27:56
here's we only consider the first
27:54 - 28:00
quadrant here's our
27:56 - 28:03
shape all right it's the hyperbola and
28:00 - 28:07
here's maybe one of our tangent lines
28:03 - 28:11
which is coming in like this and
28:07 - 28:14
then we're trying to find this area
28:11 - 28:16
here all right so there's our problem so
28:14 - 28:17
why does it have to do with Calculus it
28:16 - 28:20
has to do with Calculus because there's
28:17 - 28:23
a tangent line in it and so we're going
28:20 - 28:26
to need to do some calculus to to answer
28:23 - 28:30
this question but as you'll see the
28:26 - 28:30
calculus is the easy part
30:28 - 30:31
is and once I figured out what the
30:30 - 30:34
tangent line is the rest of the problem
30:31 - 30:37
is no longer calculus it's just that
30:34 - 30:40
slope that we need so what's the formula
30:37 - 30:46
for the tangent line put that over
30:40 - 30:47
here it's going to be Yus y0 is equal to
30:46 - 30:51
and here's the magic number we already
30:47 - 30:55
calculated it it's in the box over there
30:51 - 30:58
it's -1 /x 0^
30:58 - 31:03
so this is the only bit of calculus in
31:12 - 31:18
problem but now we're not done we have
31:16 - 31:19
to finish it we have to figure out all
31:18 - 31:22
the rest of these quantities so we can
31:19 - 31:22
figure out the
31:26 - 31:30
area all right
31:31 - 31:34
so how do we do
31:40 - 31:46
that well to find this point this has a
31:44 - 31:50
name we're going to
31:46 - 31:50
find the um so-called x
31:52 - 31:57
intercept that's the first thing we're
31:54 - 32:00
going to do so to do that what we need
31:57 - 32:03
to do is to find where this horizontal
32:00 - 32:08
line meets that diagonal line and the
32:03 - 32:10
equation for the x intercept is y =
32:10 - 32:14
right so we plug in y equals 0 that's
32:12 - 32:17
this horizontal line and we find this
32:14 - 32:22
point so let's do that into
32:17 - 32:24
star so we get 0 minus oh one other
32:22 - 32:29
thing we need to know we know that
32:24 - 32:33
y0 is f of x0 and F ofx is 1 /x so this
32:29 - 32:37
thing is 1 /
32:33 - 32:41
x0 right and that's equal to -1 /x 0^
32:37 - 32:46
2ar and here's X and here's
32:41 - 32:50
x0 all right so in order to find this x
32:46 - 32:52
value I have to uh plug in one equation
32:53 - 33:01
other so this simplifies a
32:56 - 33:07
bit uh let's put let's see this is uh -
33:01 - 33:10
xx0 2 and this is plus 1 over x0 because
33:07 - 33:14
the x0 and x0 squar cancel somewhat and
33:10 - 33:20
so if I put this on the other side I get
33:14 - 33:23
x / x 0^ 2 is equal to 2
33:20 - 33:25
x0 and if I then multiply through so
33:23 - 33:26
that's what this implies and If I
33:26 - 33:32
through by uh x0 2 I get X is equal to 2
33:39 - 33:44
okay okay so I claim that this point
33:41 - 33:44
we've just calculated it's
33:54 - 34:02
now I'm almost done I need to get the
34:00 - 34:05
other one I need to get this one up
34:02 - 34:10
here now I'm going to use a very big
34:05 - 34:10
shortcut to do that so so the
34:11 - 34:17
shortcut to the Y intercept sorry yeah
34:18 - 34:23
intercept um is to use
34:26 - 34:31
symmetry right I claim I can stare at
34:29 - 34:34
this and I can look at that and I know
34:31 - 34:36
the formula for the Y intercept it's
34:39 - 34:46
y0 all right that's what that one is so
34:42 - 34:48
this one is 2 y0 and the reason I know
34:46 - 34:51
this is the following so here's the
34:48 - 34:54
symmetry of the situation which is not
34:51 - 34:57
completely direct it's a kind of mirror
34:54 - 34:59
symmetry around the diagonal it involves
35:04 - 35:09
YX SO trading the roles of X and Y so
35:07 - 35:12
the Symmetry that I'm using is that any
35:09 - 35:14
formula I get that involves x's and y's
35:12 - 35:15
if I trade all the x's and replace them
35:14 - 35:18
by y's and trade all the Y's and replace
35:15 - 35:19
them by X's then I'll have it a correct
35:18 - 35:21
formula on the other way so everywhere I
35:19 - 35:23
see a y I'm making an X and everywhere I
35:21 - 35:27
see an X I make it a y the switch will
35:23 - 35:29
take place so why is that that's because
35:27 - 35:33
the that's just an accident of this
35:29 - 35:33
equation that's
35:34 - 35:38
because so the Symmetry
35:45 - 35:52
explained is that the equation is y = 1
35:48 - 35:55
/x but that's the same thing as XY = 1
35:52 - 35:59
If I multiply through by X which is the
35:55 - 36:02
same thing as x = 1 y so here's where
35:59 - 36:02
the X and the Y get
36:04 - 36:11
reversed okay now if you don't trust
36:07 - 36:15
this explanation you can also
36:11 - 36:15
get get the Y
36:16 - 36:20
intercept by
36:20 - 36:26
plugging xal 0 into the into the
36:29 - 36:35
okay we plugged y equals 0 in and we got
36:32 - 36:39
the x value and you could do the same
36:35 - 36:39
thing analogously the other
36:42 - 36:49
way all right so I'm almost done with
36:45 - 36:55
the with the geometry problem and uh
36:49 - 36:55
let's uh let's finish it off
36:58 - 37:02
well let me hold off for one second
37:00 - 37:04
before I finish it off what I'd like to
37:02 - 37:06
say is just make one more tiny remark
37:04 - 37:08
all right and this is the hardest part
37:06 - 37:11
of calculus in my
37:08 - 37:17
opinion so the hardest part of
37:11 - 37:20
calculus is that we call it one variable
37:17 - 37:23
calculus but we're perfectly happy to
37:20 - 37:27
deal with four variables at a time or
37:23 - 37:30
five or any number in this problem I had
37:27 - 37:33
an x a y an x0 and a y z that's already
37:30 - 37:36
four different things they have various
37:33 - 37:37
interrelationships between them so of
37:36 - 37:39
course the manipulations we do with them
37:37 - 37:41
are algebraic and when we're doing the
37:39 - 37:43
the the derivatives we just consider one
37:41 - 37:44
what's known as one variable calculus
37:43 - 37:47
but really there are millions of
37:44 - 37:49
variables floating around potentially so
37:47 - 37:50
that's what makes things complicated and
37:49 - 37:53
that's something that you have to get
37:50 - 37:55
used to now there's something else which
37:53 - 37:58
is more subtle and that I think many
37:55 - 38:00
people who teach the subject or use the
37:58 - 38:01
subject aren't aware because they've
38:00 - 38:03
already entered into the language and
38:01 - 38:06
they're not uh they're so comfortable
38:03 - 38:08
with it that they don't even notice this
38:06 - 38:12
confusion there's something deliberately
38:08 - 38:15
sloppy about the way we deal with these
38:12 - 38:17
variables the reason is very simple
38:15 - 38:19
there are already four variables here I
38:17 - 38:22
don't want to create six names for
38:19 - 38:25
variables or eight names for
38:22 - 38:28
variables and but really in this problem
38:25 - 38:32
there were about eight I just slipped
38:28 - 38:35
them by you so why is that well notice
38:32 - 38:36
that the first time that I got a formula
38:36 - 38:44
here it was this point and so the
38:40 - 38:48
formula for y0 which I plugged in right
38:44 - 38:52
here was from the the equation of the
38:48 - 38:56
curve y0 = 1x0 the second time I did it
38:52 - 38:58
I did not use y = 1X I used this
38:56 - 38:59
equation here
38:59 - 39:05
not y = 1X that's the wrong thing to do
39:03 - 39:07
that's an easy mistake to make if if the
39:05 - 39:09
formulas are all a blur to you and
39:07 - 39:13
you're not paying attention to where
39:09 - 39:15
they are on the diagram you see that Y
39:13 - 39:18
intercept that x intercept calculation
39:15 - 39:21
there involved where this horizontal
39:18 - 39:25
line met this diagonal line and Y equals
39:21 - 39:25
z represented this line
39:25 - 39:30
here so the liness is that y means two
39:30 - 39:36
things and we do this constantly because
39:33 - 39:38
it's way way more complicated not to do
39:36 - 39:40
it Con to do it it's much more
39:38 - 39:43
convenient for us to allow ourselves a
39:40 - 39:47
flexibility to change the role that this
39:43 - 39:49
letter plays in the middle of the of the
39:47 - 39:50
computation and similarly later on if I
39:49 - 39:54
had done this by this more
39:50 - 39:56
straightforward method for the uh Y
39:54 - 39:57
intercept I would have set x equal to Z
39:56 - 40:01
that would have been this vertical line
39:57 - 40:03
which is x equals 0 but I didn't change
40:01 - 40:07
the letter X when I did that because
40:03 - 40:08
that would be a waste for us so this
40:07 - 40:11
this is this is one of the main
40:08 - 40:13
confusions that happens if you can uh
40:11 - 40:17
keep yourself straight you're you're a
40:13 - 40:21
lot better off and and as I say this is
40:17 - 40:24
this is uh this is one of the
40:21 - 40:25
complexities all right so now let's
40:24 - 40:29
finish off the problem and let me
40:25 - 40:29
finally get this area here
40:31 - 40:37
so actually I'll just finish it off
40:32 - 40:37
right here so the area of the
40:39 - 40:45
triangle is well it's the base times the
40:42 - 40:49
height the base is 2x0 the height is 2
40:45 - 40:55
y0 and a half of that so it's a half 2x0
40:49 - 40:58
* 2 y0 which is 2 x0 y0 which is lo and
40:58 - 41:01
so the amusing thing in this case is it
41:00 - 41:05
actually didn't matter what x0 and Y Z
41:01 - 41:08
are we get the same answer every
41:05 - 41:11
time that's just an accident of the
41:08 - 41:14
function 1 /x happens to be the function
41:19 - 41:25
property all right so we have still have
41:22 - 41:29
more business today serious business so
41:25 - 41:29
let me continue
41:31 - 41:36
so first of all I want to give you a few
41:42 - 41:47
and these are just other ways that
41:47 - 41:53
uh refer uh notations that people use to
41:50 - 41:55
refer to derivatives and the first one
41:53 - 41:58
is the following we already wrote Y is
41:55 - 42:00
equal to F ofx and so when we write
41:58 - 42:07
deltay that means the same thing as
42:00 - 42:13
Delta F that's a typical notation and
42:07 - 42:16
previously we wrote um f Prime for the
42:13 - 42:19
derivative so this is this is so this is
42:16 - 42:22
Newton's notation for the
42:19 - 42:25
derivative okay but there are other
42:22 - 42:28
notations and one of them is DF
42:25 - 42:31
DX and another one is d ydx meaning
42:28 - 42:34
exactly the same thing and sometimes we
42:31 - 42:38
let the function slip down below so that
42:34 - 42:42
becomes d by DX of f or D by
42:38 - 42:45
DX of Y so these are all notations that
42:42 - 42:48
are used for the derivative and these
42:45 - 42:48
were initiated by
42:50 - 42:56
and these notations are um used
42:53 - 42:58
interchangeably sometimes uh practically
42:56 - 43:02
together they both turn out to be
42:58 - 43:05
extremely useful this one omits notice
43:02 - 43:08
that this thing omits the uh underlying
43:05 - 43:10
base Point x0 that's one of the
43:08 - 43:14
nuisances it doesn't give you all the
43:10 - 43:16
information but there are lots of uh
43:14 - 43:19
situations like that
43:16 - 43:20
where where uh people leave out some of
43:19 - 43:24
the important information you have to
43:20 - 43:28
fill it in from Context so that's
43:24 - 43:31
another couple of notations
43:28 - 43:34
so now I have one more calculation for
43:31 - 43:37
you today uh I carried out this
43:34 - 43:41
calculation of the derivative of the
43:42 - 43:48
um the the derivative of the function 1
43:45 - 43:51
/x I want to take care of some other
43:48 - 43:51
powers so let's do
44:03 - 44:13
two is going to be the function F ofx is
44:07 - 44:16
X to the n and = 1 2 3 one of these
44:13 - 44:19
guys and now what we're trying to figure
44:16 - 44:22
out is the derivative with respect to X
44:19 - 44:25
of x to the n in our new new notation
44:22 - 44:25
what this is equal
44:28 - 44:36
so again we're going to form this
44:31 - 44:38
expression Delta F Delta X and we're
44:36 - 44:40
going to make some algebraic
44:38 - 44:45
simplification so what we plug in for
44:40 - 44:50
Delta f is X+ Delta x to the N minus X
44:45 - 44:52
the N / Delta X now before let me just
44:50 - 44:57
stick this in and I'm going to erase it
44:52 - 45:00
before I wrote x0 here and x0 there but
44:57 - 45:02
now I'm going to get rid of it because
45:00 - 45:03
in this particular calculation it's a
45:02 - 45:05
nuisance I don't have an X floating
45:03 - 45:07
around which means something different
45:05 - 45:09
from the X zero and I just don't want to
45:07 - 45:13
have to keep on writing all those
45:09 - 45:15
symbols it's a waste of Blackboard uh
45:13 - 45:17
energy uh there's a total amount of
45:15 - 45:20
energy that I'm you know I've already
45:17 - 45:22
filled up so many blackboards that it's
45:20 - 45:25
just a limited amount of plus I'm trying
45:22 - 45:29
to conserve chalk okay anyway no
45:25 - 45:31
zeros so think of X is fixed again um in
45:29 - 45:35
this case Delta X
45:31 - 45:39
moves and X is
45:35 - 45:41
fixed in this in this
45:39 - 45:43
calculation all right now in order to
45:41 - 45:45
simplify this in order to understand
45:43 - 45:47
algebraically what's going on I need to
45:45 - 45:50
understand what the nth power of a sum
45:47 - 45:54
is and that's a famous formula we only
45:50 - 45:58
need a little tiny bit of it called the
45:54 - 46:01
binomial theorem so the binomial
46:03 - 46:08
theorem which is in your
46:05 - 46:12
text and uh explained in an in an
46:08 - 46:15
exercise says uh in an appendex sorry
46:12 - 46:17
says that if you take the sum of two
46:15 - 46:20
guys and you take them to the nth power
46:17 - 46:24
that of course is X Plus Delta
46:20 - 46:28
X multiplied by itself n
46:24 - 46:30
times and so the first term
46:28 - 46:34
is X to the N that's when all of the N
46:30 - 46:36
factors come in and then you could have
46:34 - 46:39
this factor of Delta X and all the rest
46:36 - 46:42
X's so at least one term of the form X
46:39 - 46:45
the n minus1 * Delta X and how many
46:42 - 46:46
times does that happen well it happens
46:45 - 46:48
when there's a factor from here from the
46:46 - 46:50
next factor and so on and so on and so
46:48 - 46:53
on there's a total of n
46:50 - 46:57
possible times that that
46:53 - 47:00
happens and now the great thing is that
46:57 - 47:03
with this alone all the rest of the
47:04 - 47:10
junk that we won't have to worry about
47:07 - 47:12
so to be more specific the junk there's
47:10 - 47:17
a very careful notation for the junk the
47:12 - 47:22
junk is what's called Big O of Delta x
47:17 - 47:22
s what that means is that these are
47:22 - 47:29
terms of order uh so with
47:29 - 47:36
X2 Delta X cubed or
47:33 - 47:36
higher right that's
47:40 - 47:47
exciting higher order terms okay so this
47:45 - 47:49
is the only algebra that we need to do
47:47 - 47:52
and now we just need to combine it
47:49 - 47:55
together to get our result so now I'm
47:52 - 47:59
going to just carry out the
47:55 - 47:59
cancellations that we
48:01 - 48:10
need so here we go we
48:05 - 48:14
have Delta F over Delta X which remember
48:10 - 48:14
was 1/ Delta X time
48:17 - 48:30
this which is this times now this is X
48:21 - 48:30
the n + n x nus1 Delta X plus this junk
48:31 - 48:37
term minus x to the
48:34 - 48:41
N all right so that's what we have so
48:37 - 48:44
far based on our previous
48:41 - 48:47
calculations now I'm going to do the
48:44 - 48:50
main C cancellation which is
48:47 - 48:59
this all right so that's one over Delta
48:50 - 48:59
x * n x nus1 Delta X plus this term
49:00 - 49:09
here and now I can divide in by Delta X
49:05 - 49:12
so I get N X nus1 Plus now it's O of
49:09 - 49:14
Delta X there's at least one factor of
49:12 - 49:17
Delta X not two factors of Delta X
49:14 - 49:20
because I have to cancel one of
49:17 - 49:21
them and now I can just take the limit
49:20 - 49:25
in the limit this term is going to be
49:21 - 49:28
zero that's why I called it junk
49:25 - 49:31
originally because it disapp appears and
49:28 - 49:35
in math junk is something that goes away
49:31 - 49:39
so this tends to as Delta X goes to zero
49:35 - 49:40
n x n minus1 and so what I've shown you
49:40 - 49:49
that d by DX of x n minus sorry n is
49:45 - 49:49
equal to n x nus
49:50 - 49:55
one so now this is going to be super
49:52 - 49:57
important to you right on your problem
49:55 - 49:59
set in every possible way and I want to
49:57 - 50:01
tell you one thing one way in which it's
49:59 - 50:05
very important and one way that extends
50:01 - 50:05
it immediately so this thing
50:10 - 50:17
pols we get quite a lot out of this one
50:13 - 50:21
calculation namely if I take d by DX of
50:17 - 50:24
something like X cubed + 5 x 10th
50:21 - 50:26
power that's going to be equal to
50:24 - 50:32
3x^2 that's applying this rule to X
50:26 - 50:36
cubed and then here I'll get 5 * 10 so
50:32 - 50:38
50 x 9th so this is the type of thing
50:36 - 50:43
that we get out of it and we're going to
50:38 - 50:43
make more hay with that next
50:48 - 50:54
time question yes I turn myself off
50:57 - 51:03
the question is the question was the
51:00 - 51:05
binomial theorem only works when x uh
51:03 - 51:08
Delta X goes to zero no the the binomial
51:05 - 51:10
theorem is a general formula which also
51:08 - 51:13
specifies exactly what the junk is it's
51:10 - 51:15
very much more detailed but we only
51:13 - 51:18
needed this part we didn't care what all
51:15 - 51:21
these crazy terms
51:18 - 51:24
were it's it's it's junk for our
51:21 - 51:28
purposes now because we don't happen to
51:24 - 51:30
need any more than those first two terms
51:28 - 51:34
yes because the death Lex goes to zero
51:30 - 51:34
okay see you next time